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Rhenium(V) chloride react with boron(III) bromide

6ReCl5 + 10BBr3 → 6ReBr4 + 3Br2 + 10BCl3

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Rhenium(V) chloride react with boron(III) bromide to produce rhenium(IV) bromide, bromine and boron(III) chloride. This reaction takes place at a temperature near 100°C.

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Сoding to search: 6 ReCl5 + 10 BBr3 cnd [ temp ] = 6 ReBr4 + 3 Br2 + 10 BCl3

Add / Edited: 18.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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