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Ruthenium react with bromine(III) fluoride
6Ru + 16BrF
3
→ 6(BrF
2
)[RuF
6
] + 5Br
2
[ Check the balance ]
Ruthenium react with bromine(III) fluoride to produce difluorobromine(III) hexafluororuthenate(V) and bromine. Bromine(III) fluoride - liquid. This reaction takes place at a temperature near 20°C.
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Picture of reaction:
Сoding to search:
6 Ru + 16 BrF3 = 6 BrF2RuF6 + 5 Br2
Add / Edited:
20.07.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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