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Ruthenium react with bromine(III) fluoride

6Ru + 16BrF3 → 6(BrF2)[RuF6] + 5Br2


Ruthenium react with bromine(III) fluoride to produce difluorobromine(III) hexafluororuthenate(V) and bromine. Bromine(III) fluoride - liquid. This reaction takes place at a temperature near 20°C.


Picture of reaction: img1 BB html

Сoding to search: 6 Ru + 16 BrF3 = 6 BrF2RuF6 + 5 Br2

Add / Edited: 20.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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