RuO4 + KCl + HCl = K4[Ru2Cl10O] + Cl2 + H2O |

2RuO₄ + 4KCl + 14HCl → K₄[Ru₂Cl₁₀O] + 4Cl₂ + 7H₂O

Ruthenium(VIII) oxide react with potassium chloride and hydrogen chloride to produce potassium oxodecachloridodiruthenate(IV), chlorine and water. Potassium chloride and hydrogen chloride - concentrated solutions.

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Ruthenium(VIII) oxide react with potassium chloride and hydrogen chloride

2RuO₄ + 4KCl + 14HCl → K₄[Ru₂Cl₁₀O] + 4Cl₂ + 7H₂O

Picture of reaction:

Сoding to search: 2 RuO4 + 4 KCl + 14 HCl = K4Ru2Cl10O + 4 Cl2 + 7 H2O

Add / Edited: 20.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Ruthenium(VIII) oxide react with potassium chloride and hydrogen chloride

2RuO4 + 4KCl + 14HCl → K4[Ru2Cl10O] + 4Cl2 + 7H2O

Picture of reaction:

Сoding to search: 2 RuO4 + 4 KCl + 14 HCl = K4Ru2Cl10O + 4 Cl2 + 7 H2O

Add / Edited: 20.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2RuO₄ + 4KCl + 14HCl → K₄[Ru₂Cl₁₀O] + 4Cl₂ + 7H₂O

Add / Edited: 20.07.2015 /