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Sulfur hexafluoride react with hydrogen iodide

SF6 + 8HI → H2S + 4I2 + 6HF

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Sulfur hexafluoride react with hydrogen iodide to produce hydrogen sulfide, iodine and hydrogen fluoride. This reaction takes place at a temperature near 200°C.

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Сoding to search: SF6 + 8 HI cnd [ temp ] = H2S + 4 I2 + 6 HF

Add / Edited: 21.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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