SbI3 + HNO3 = Sb2O5 + I2 + NO2 + H2O |

2SbI₃ + 10HNO₃ Sb₂O₅ + 3I₂ + 10NO₂ + 5H₂O

Antimony(III) iodide react with nitric acid to produce antimony(V) oxide, iodine, nitrogen dioxide and water. Nitric acid - concentrated solution. The reaction takes place in a boiling solution.

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Antimony(III) iodide react with nitric acid

2SbI₃ + 10HNO₃ Sb₂O₅ + 3I₂ + 10NO₂ + 5H₂O

Picture of reaction:

Сoding to search: 2 SbI3 + 10 HNO3 cnd [ temp ] = Sb2O5 + 3 I2 + 10 NO2 + 5 H2O

Add / Edited: 26.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Antimony(III) iodide react with nitric acid

2SbI3 + 10HNO3 Sb2O5 + 3I2 + 10NO2 + 5H2O

Picture of reaction:

Сoding to search: 2 SbI3 + 10 HNO3 cnd [ temp ] = Sb2O5 + 3 I2 + 10 NO2 + 5 H2O

Add / Edited: 26.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2SbI₃ + 10HNO₃ Sb₂O₅ + 3I₂ + 10NO₂ + 5H₂O

Add / Edited: 26.07.2015 /