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Samarium react with samarium(III) fluoride

Sm + 2SmF3 → 3SmF2


Samarium react with samarium(III) fluoride to produce samarium(II) fluoride. This reaction takes place at a temperature near 950°C.


Picture of reaction: img1 BB html

Сoding to search: Sm + 2 SmF3 cnd [ temp ] = 3 SmF2

Add / Edited: 01.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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