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Samarium react with samarium(III) chloride

Sm + 2SmCl3 → 3SmCl2


Samarium react with samarium(III) chloride to produce samarium(II) chloride. This reaction takes place at a temperature near 800°C in a argon atmosphere.


Picture of reaction: img1 BB html

Сoding to search: Sm + 2 SmCl3 cnd [ temp ] = 3 SmCl2

Add / Edited: 01.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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