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Samarium react with samarium(III) sulfide

4Sm + Sm2S3 → 3Sm2S

[ Check the balance ]
Samarium react with samarium(III) sulfide to produce samarium(I) sulfide. This reaction takes place at a temperature of 600-1000°C.

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Сoding to search: 4 Sm + Sm2S3 cnd [ temp ] = 3 Sm2S

Add / Edited: 01.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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