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Tin(IV) chloride react with lithium tetrahydroxoaluminate(III)

SnCl4 + Li[AlH4] → SnH4 + LiCl + AlCl3


Tin(IV) chloride react with lithium tetrahydroxoaluminate(III) to produce tin(IV) hydride, lithium chloride and aluminum chloride. This reaction takes place in the medium of ester, at a temperature near -20°C.


Picture of reaction: img1 BB html

Сoding to search: SnCl4 + LiAlH4 = SnH4 + LiCl + AlCl3

Add / Edited: 11.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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