Sn(OH)2 + Bi(NO3)3 + NaOH = Na2[Sn(OH)6] + Bi + NaNO3 |

3Sn(OH)₂ + 2Bi(NO₃)₃ + 12NaOH → 3Na₂[Sn(OH)₆] + 2Bi + 6NaNO₃

Tin(II) hydroxide react with nitrate bismuth and sodium hydroxide to produce sodium hexahydroxostannate(IV), bismuth and sodium nitrate. Sodium hydroxide - concentrated solution.

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Tin(II) hydroxide react with nitrate bismuth and sodium hydroxide

3Sn(OH)₂ + 2Bi(NO₃)₃ + 12NaOH → 3Na₂[Sn(OH)₆] + 2Bi + 6NaNO₃

Picture of reaction:

Сoding to search: 3 SnOH2 + 2 BiNO33 + 12 NaOH = 3 Na2SnOH6 + 2 Bi + 6 NaNO3

Add / Edited: 11.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Tin(II) hydroxide react with nitrate bismuth and sodium hydroxide

3Sn(OH)2 + 2Bi(NO3)3 + 12NaOH → 3Na2[Sn(OH)6] + 2Bi + 6NaNO3

Picture of reaction:

Сoding to search: 3 SnOH2 + 2 BiNO33 + 12 NaOH = 3 Na2SnOH6 + 2 Bi + 6 NaNO3

Add / Edited: 11.08.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

3Sn(OH)₂ + 2Bi(NO₃)₃ + 12NaOH → 3Na₂[Sn(OH)₆] + 2Bi + 6NaNO₃

Add / Edited: 11.08.2015 /