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Tellurium react with fluorine and rubidium fluoride

Te + 3F2 + 2RbF → Rb2[TeF8]

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Tellurium react with fluorine and rubidium fluoride to produce rubidium oktafluorotellurate(VI). This reaction takes place at a temperature near 75°C.

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Сoding to search: Te + 3 F2 + 2 RbF cnd [ temp ] = Rb2TeF8

Add / Edited: 13.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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