TeO2 = TeO + O2 |

3TeO₂ ⇄ 2TeO + O₂

The thermal decomposition of tellurium(IV) oxide to produce oxide tellurium(II) and oxygen. This reaction takes place at a temperature of over 1000°C.

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The thermal decomposition of tellurium(IV) oxide

3TeO₂ ⇄ 2TeO + O₂

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Сoding to search: 3 TeO2 cnd [ temp ] = 2 TeO + O2

Add / Edited: 13.08.2015 /

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The thermal decomposition of tellurium(IV) oxide

3TeO2 ⇄ 2TeO + O2

Picture of reaction:

Сoding to search: 3 TeO2 cnd [ temp ] = 2 TeO + O2

Add / Edited: 13.08.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

3TeO₂ ⇄ 2TeO + O₂

Add / Edited: 13.08.2015 /