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Tellurium(VI) oxide react with hydrogen fluoride and sodium fluoride

TeO3 + 4HF + NaF → Na[TeOF5] + 2H2O


Tellurium(VI) oxide react with hydrogen fluoride and sodium fluoride to produce sodium pentafluorooxotellurate(VI) and water. Hydrogen fluoride - liquid. The reaction proceeds at room temperature.


Picture of reaction: img1 BB html

Сoding to search: TeO3 + 4 HF + NaF = NaTeOF5 + 2 H2O

Add / Edited: 13.08.2015 /

Evaluation of information: 4.0 out of 5 / number of votes: 1


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