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Hexacarbonylvanadium react with iodine

2[V(CO)6] + 3I2 → 2VI3 + 12CO


Hexacarbonylvanadium react with iodine to produce vanadium(III) iodide and carbon monoxide. The reaction takes place in a boiling solution in the medium of ester.


Picture of reaction: img1 BB html

Сoding to search: 2 VCO6 + 3 I2 cnd [ temp ] = 2 VI3 + 12 CO

Add / Edited: 16.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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