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Vanadium(III) oxide react with thionyl chloride

V2O3 + 3SOCl2 → 2VCl3 + 3SO2

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Vanadium(III) oxide react with thionyl chloride to produce vanadium(III) chloride and sulfur dioxide. This reaction takes place at a temperature near 200°C and an overpressure.

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Сoding to search: V2O3 + 3 SOCl2 cnd [ temp ] = 2 VCl3 + 3 SO2

Add / Edited: 16.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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