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The thermal decomposition of vanadium(V) sulfide

V2S5 → V2S3 + 2S


The thermal decomposition of vanadium(V) sulfide to produce vanadium(III) sulfide and sulfur. This reaction takes place at a temperature of 400-500°C.


Picture of reaction: img1 BB html

Сoding to search: V2S5 cnd [ temp ] = V2S3 + 2 S

Add / Edited: 17.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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