V2S5 + O2 = V2O5 + SO2 |

2V₂S₅ + 15O₂ 2V₂O₅ + 10SO₂

Vanadium(V) sulfide react with oxygen to produce vanadium(V) oxide sulfur dioxide. This reaction takes place at a temperature of 500-600°C.

Interaction vanadium(V) sulfide with atmospheric oxygen.

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Periodic table of elements

Vanadium(V) sulfide react with oxygen

2V₂S₅ + 15O₂ 2V₂O₅ + 10SO₂

Picture of reaction:

Сoding to search: 2 V2S5 + 15 O2 cnd [ temp ] = 2 V2O5 + 10 SO2

Add / Edited: 17.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Vanadium(V) sulfide react with oxygen

2V2S5 + 15O2 2V2O5 + 10SO2

Picture of reaction:

Сoding to search: 2 V2S5 + 15 O2 cnd [ temp ] = 2 V2O5 + 10 SO2

Add / Edited: 17.08.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2V₂S₅ + 15O₂ 2V₂O₅ + 10SO₂

Add / Edited: 17.08.2015 /