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Vanadium(II) sulfate react with sulfuric acid

2VSO4 + H2SO4 → V2(SO4)3 + H2


Vanadium(II) sulfate react with sulfuric acid to produce vanadium(II) sulfate and water. Sulfuric acid - diluted solution. This reaction slowly takes place at a temperature of 20-80°C.


Picture of reaction: img1 BB html

Сoding to search: 2 VSO4 + H2SO4 = V2SO43 + H2

Add / Edited: 17.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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