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The thermal decomposition of vanadium(III) sulfate

V2(SO4)3 → 2VOSO4 + SO2


The thermal decomposition of vanadium(III) sulfate to produce vanadyl sulfate and sulfur dioxide. This reaction takes place at a temperature of 300-400°C. Impurities: vanadium(III) oxide V2O3, oxide sulfur(VI) SO3.
 


Picture of reaction: img1 BB html

Сoding to search: V2SO43 cnd [ temp ] = 2 VOSO4 + SO2

Add / Edited: 17.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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