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The thermal decomposition of vanadium(III) sulfate
V
2
(SO
4
)
3
2VOSO
4
+ SO
2
[ Check the balance ]
The thermal decomposition of vanadium(III) sulfate to produce vanadyl sulfate and sulfur dioxide. This reaction takes place at a temperature of 300-400°C. Impurities: vanadium(III) oxide V
2
O
3
, oxide sulfur(VI) SO
3
.
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Picture of reaction:
Сoding to search:
V2SO43 cnd [ temp ] = 2 VOSO4 + SO2
Add / Edited:
17.08.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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