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Difluorobromine(III) hexafluoroantimonate(V) react with tetrafluorobromate(III) silver(I)
[BrF
2
][SbF
6
] + Ag[BrF
4
] → Ag[SbF
6
] + 2BrF
3
[ Check the balance ]
Difluorobromine(III) hexafluoroantimonate(V) react with tetrafluorobromate(III) silver(I) to produce hexafluoroantimonate(V) silver(I) and bromine(III) fluoride.
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Picture of reaction:
Сoding to search:
BrF2SbF6 + AgBrF4 = AgSbF6 + 2 BrF3
Add / Edited:
26.08.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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