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Difluorobromine(III) hexafluoroantimonate(V) react with tetrafluorobromate(III) silver(I)

[BrF2][SbF6] + Ag[BrF4] → Ag[SbF6] + 2BrF3


Difluorobromine(III) hexafluoroantimonate(V) react with tetrafluorobromate(III) silver(I) to produce hexafluoroantimonate(V) silver(I) and bromine(III) fluoride.


Picture of reaction: img1 BB html

Сoding to search: BrF2SbF6 + AgBrF4 = AgSbF6 + 2 BrF3

Add / Edited: 26.08.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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