Home Reactions Blog
Language: ru es en
Chemiday Chemiday Log in:


The reaction between palladium oxide (3) with hydrochloric acid to form chloride of palladium and gaseous chlorine, water

2Pd2O3•H2O + 6HCl → 2PdCl2 + Cl2 + 5H2O


The reaction between palladium oxide (3) with hydrochloric acid to form chloride of palladium and gaseous chlorine, water.

Our channel




Picture of reaction: img1 BB html

Сoding to search: Pd2O3 2 • H2O + 6 HCl = 2 PdCl2 + Cl2 + 5 H2O

Add / Edited: 15.09.2019 /

Evaluation of information: 0.0 out of 5 / number of votes: 0


Please register to post comments

Become a Patron!
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | VK page
ChemiDay.com © 2019
This site uses «cookies». Terms of use «cookies» look at Cookies policy and User's agreement. The site also uses internet-service for collecting technical data about users for to collect marketing and statistical information. Terms of use user's data look at Privacy policy.