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The reaction of interaction of bromide with palladium bromatological by acid tetrabromophthalate (2)

PdBr2 + 2HBr → H2[PdBr4]


The reaction of interaction of bromide with palladium bromatological by acid tetrabromophthalate (2).


Picture of reaction: img1 BB html

Сoding to search: PdBr2 + 2 HBr = H2PdBr4

Add / Edited: 15.09.2019 /

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