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The reaction between salts of iridium(4) with a solution of hydrogen sulfide with the formation of sulphide of iridium(3), sulfur, and hydrochloric acid

2H2[IrCl6] + 4H2S → Ir2S3 + S + 12HCl


The reaction between salts of iridium(4) with a solution of hydrogen sulfide with the formation of sulphide of iridium(3), sulfur, and hydrochloric acid.


Picture of reaction: img1 BB html

Сoding to search: 2 H2IrCl6 + 4 H2S = Ir2S3 + S + 1 2HCl

Add / Edited: 15.09.2019 /

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