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The reaction between dibromide-iodide of boron with water to form a hydroxide of boron, hydrogen bromide, of iododerma
BBr
2
I + 3H
2
O → B(OH)
3
+ 2HBr + HI
[ Check the balance ]
The reaction between dibromide-iodide of boron with water to form a hydroxide of boron, hydrogen bromide, of iododerma.
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BBr2I + 3 H2O = BOH3 + 2 HBr + HI
Add / Edited:
15.09.2019 /
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