Home Reactions Blog
Language: ru es en
Chemiday Chemiday Log in:


The reaction between bradybaena with water to form boric acid, hydrogen bromide, hydrogen

B2H5Br + 6H2O → 2H3BO3 + HBr + 5H2


The reaction between bradybaena with water to form boric acid, hydrogen bromide, hydrogen.

Our channel




Picture of reaction: img1 BB html

Сoding to search: B2H5Br + 6 H2O = 2 H3BO3 + HBr + 5 H2

Add / Edited: 15.09.2019 /

Evaluation of information: 0.0 out of 5 / number of votes: 0


Please register to post comments

Become a Patron!
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | VK page
ChemiDay.com © 2019
This site uses «cookies». Terms of use «cookies» look at Cookies policy and User's agreement. The site also uses internet-service for collecting technical data about users for to collect marketing and statistical information. Terms of use user's data look at Privacy policy.