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The reaction between bradybaena with water to form boric acid, hydrogen bromide, hydrogen

B2H5Br + 6H2O → 2H3BO3 + HBr + 5H2

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The reaction between bradybaena with water to form boric acid, hydrogen bromide, hydrogen.

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Сoding to search: B2H5Br + 6 H2O = 2 H3BO3 + HBr + 5 H2

Add / Edited: 15.09.2019 /

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