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The reaction between excess DIBORANE with chlorine with the formation of hardeberga and hydrogen chloride

B2H6 + Cl2 → B2H5Cl + HCl


The reaction between excess DIBORANE with chlorine with the formation of hardeberga and hydrogen chloride.

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Picture of reaction: img1 BB html

Сoding to search: B2H6 is + Cl2 = B2H5Cl + HCl

Add / Edited: 15.09.2019 /

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