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The reaction of interaction of tetrahydridoborate of beryllium with water to form a hydroxide of beryllium, boron hydroxide, hydrogen

Be[BH4]2 + 8H2O → Be(OH)2 + 2B(OH)3 + 8H2

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The reaction of interaction of tetrahydridoborate of beryllium with water to form a hydroxide of beryllium, boron hydroxide, hydrogen.

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Сoding to search: BeBH42 + 8 H2O = BeOH2 + BOH3 2 + 8 H2

Add / Edited: 15.09.2019 /

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