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The reaction between anhydrous acetic acid with metallic aluminum in the presence of iodine with the formation of acetate of aluminum and hydrogen

2Al + 6CH3COOH → 2Al(CH3COO)3 + 3H2

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The reaction between anhydrous acetic acid with metallic aluminum in the presence of iodine with the formation of acetate of aluminum and hydrogen.

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Сoding to search: 2 Al + 6 CH3COOH = 2 AlCH3COO3 + 3 H2

Add / Edited: 20.09.2019 /

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