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The reaction between hydrogen and chloride of zirconium(IV) bromide and boron with the formation of zirconium diboride and hydrochloric acid

ZrCl4 + 2BBr3 + 5H2 → ZrBr2 + 4HCl + 6HBr


The reaction between hydrogen and chloride of zirconium(IV) bromide and boron with the formation of zirconium diboride and hydrochloric acid.

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Picture of reaction: img1 BB html

Сoding to search: ZrCl4 + 2 BBr3 + H2 5 = ZrBr2 + 4 HCl + 6 HBr

Add / Edited: 20.09.2019 /

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