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The reduction reaction of tetrabromide of hafnium aluminum

3HfBr4 + Al → HfBr3 + AlBr3

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The reduction reaction of tetrabromide of hafnium aluminum.

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Сoding to search: 3 HfBr4 + Al = HfBr3 + AlBr3

Add / Edited: 29.09.2019 /

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