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The reaction of the electrolysis of a suspension of vanadium oxide(V) in dilute hydrochloric acid

V2O5 + 10HCl → 2VCl3 + 2Cl2 + 5H2O


The reaction of the electrolysis of a suspension of vanadium oxide(V) in dilute hydrochloric acid.


Picture of reaction: img1 BB html

Сoding to search: V2O5 + 10 HCl = 2 VCl3 + 2 Cl2 + 5 H2O

Add / Edited: 29.09.2019 /

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