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The reaction between niobium, chromate(VI) sodium and sodium hydroxide with the formation of orthonomal(V) sodium chromite, sodium and water

3Nb + 5Na2CrO4 + 4NaOH → 3Na3NbO4 + 5NaCrO2 + 2H2O

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The reaction between niobium, chromate(VI) sodium and sodium hydroxide with the formation of orthonomal(V) sodium chromite, sodium and water.

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Сoding to search: 3 Nb + 5 Na2CrO4 + 4 NaOH = 3 Na3NbO4 + 5 NaCrO2 + 2 H2O

Add / Edited: 21.10.2019 /

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