MoCl5 + HI = MoI2 + I2 +HCl |

2MoCl₅ + 10HI → 2MoI₂ + 3I₂ +10HCl

The reaction between chloride of molybdenum(V) and idolatrada with the formation of iodide of molybdenum(II), iodine and hydrochloric acid. The equation of the reaction.

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The reaction between chloride of molybdenum(V) and idolatrada with the formation of iodide of molybdenum(II), iodine and hydrochloric acid. The equation of the reaction

2MoCl₅ + 10HI → 2MoI₂ + 3I₂ +10HCl

Picture of reaction:

Сoding to search: 2 MoCl5 + 10 HI = 2 MoI2 + 3 I2 + 10 HCl

Add / Edited: 21.10.2019 /

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The reaction between chloride of molybdenum(V) and idolatrada with the formation of iodide of molybdenum(II), iodine and hydrochloric acid. The equation of the reaction

2MoCl5 + 10HI → 2MoI2 + 3I2 +10HCl

Picture of reaction:

Сoding to search: 2 MoCl5 + 10 HI = 2 MoI2 + 3 I2 + 10 HCl

Add / Edited: 21.10.2019 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2MoCl₅ + 10HI → 2MoI₂ + 3I₂ +10HCl

Add / Edited: 21.10.2019 /