Mo + HF + HNO3 = MoOF4 + NO + H2O |

Mo + 4HF + 2HNO₃ → MoOF₄ + 2NO + 3H₂O

The reaction of interaction of molybdenum with hydrogen fluoride and nitric acid with the formation of oxitetraciclina molybdenum(VI) oxide nitrogen(II) and water.

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The reaction of interaction of molybdenum with hydrogen fluoride and nitric acid with the formation of oxitetraciclina molybdenum(VI) oxide nitrogen(II) and water

Mo + 4HF + 2HNO₃ → MoOF₄ + 2NO + 3H₂O

Picture of reaction:

Сoding to search: Mo + 4 HF + 2 HNO3 = MoOF4 + 2 NO + 3 H2O

Add / Edited: 21.10.2019 /

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The reaction of interaction of molybdenum with hydrogen fluoride and nitric acid with the formation of oxitetraciclina molybdenum(VI) oxide nitrogen(II) and water

Mo + 4HF + 2HNO3 → MoOF4 + 2NO + 3H2O

Picture of reaction:

Сoding to search: Mo + 4 HF + 2 HNO3 = MoOF4 + 2 NO + 3 H2O

Add / Edited: 21.10.2019 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

Mo + 4HF + 2HNO₃ → MoOF₄ + 2NO + 3H₂O

Add / Edited: 21.10.2019 /