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The reaction between the fluoride of molybdenum(III), water and oxygen to form molybdenum oxide(VI) and hydrogen fluoride

4MoF3 + 6H2O + 3O2 → 4MoO3 + 12HF




The reaction between the fluoride of molybdenum(III), water and oxygen to form molybdenum oxide(VI) and hydrogen fluoride.


Picture of reaction: img1 BB html

Сoding to search: 4 MoF3 + 6 H2O + 3 O2 = 4 MoO3 + 12 HF

Add / Edited: 21.10.2019 /

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