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The reduction reaction of the chloride of bismuth(III) a carbide of aluminum in acidic medium with the formation of trimethylamine and chloride of aluminum

BiCl3 + Al4C3 + 9HCl → Bi(CH3)3 + 4AlCl3


The reduction reaction of the chloride of bismuth(III) a carbide of aluminum in acidic medium with the formation of trimethylamine and chloride of aluminum.


Picture of reaction: img1 BB html

Сoding to search: BiCl3 + Al4C3 + 9 HCl = BiCH33 + 4 AlCl3

Add / Edited: 21.10.2019 /

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