PoO2 + HCl = PoCl4 + H2O |

PoO₂ + 4HCl → PoCl₄ + 2H₂O

The reaction between the oxide of polonium(IV) and hydrochloric acid with the formation of the chloride of polonium(IV) and water (polonium is radioactive and has no stable isotopes).

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The reaction between the oxide of polonium(IV) and hydrochloric acid with the formation of the chloride of polonium(IV) and water (polonium is radioactive and has no stable isotopes)

PoO₂ + 4HCl → PoCl₄ + 2H₂O

Picture of reaction:

Сoding to search: TMG EV poo2 + 4 HCl = PoCl4 + 2 H2O

Add / Edited: 21.10.2019 /

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The reaction between the oxide of polonium(IV) and hydrochloric acid with the formation of the chloride of polonium(IV) and water (polonium is radioactive and has no stable isotopes)

PoO2 + 4HCl → PoCl4 + 2H2O

Picture of reaction:

Сoding to search: TMG EV poo2 + 4 HCl = PoCl4 + 2 H2O

Add / Edited: 21.10.2019 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

PoO₂ + 4HCl → PoCl₄ + 2H₂O

Add / Edited: 21.10.2019 /