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The reaction between bromide tantalum(II) and water with the formation of bromide of tantalum(III) hydroxide of tantalum(III) and hydrogen

6TaBr2 + 6H2O → 4TaBr3 + 2Ta(OH)3 + 3H2


The reaction between bromide tantalum(II) and water with the formation of bromide of tantalum(III) hydroxide of tantalum(III) and hydrogen.


Picture of reaction: img1 BB html

Сoding to search: 6 TaBr2 + 6 H2O = 4 TaBr3 + 2 TaOH3 + 3 H2

Add / Edited: 21.10.2019 /

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