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The reaction between bromide tantalum(III) and water with the formation of hydrated oxide of tantalum(II), of hydrogen bromide and hydrogen

2TaBr3 + 6H2O → 2TaO2*2H2O + 6HBr + H2


The reaction between bromide tantalum(III) and water with the formation of hydrated oxide of tantalum(II), of hydrogen bromide and hydrogen.

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Сoding to search: 2 TaBr3 + 6 H2O = 2 TaO2*2H2O + 6 HBr + H2

Add / Edited: 21.10.2019 /

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