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The reaction between the hydroxide of thallium(III) and sulfuric acid with the formation of sulphate of thallium(III) and water

2Tl(OH)3 + 3H2SO4 → Tl2(SO4)3 + 6H2O


The reaction between the hydroxide of thallium(III) and sulfuric acid with the formation of sulphate of thallium(III) and water.


Picture of reaction: img1 BB html

Сoding to search: TlOH3 2 + 3 H2SO4 = Tl2SO43 + 6 H2O

Add / Edited: 11.12.2019 /

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