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The reaction between chloride of thallium(I), metallitia and methyl iodide with the formation of trimethylsily, lithium chloride and lithium iodide

TlCl + 2LiCH3 + CH3I → Tl(CH3)3 + LiCl + LiI


The reaction between chloride of thallium(I), metallitia and methyl iodide with the formation of trimethylsily, lithium chloride and lithium iodide.


Picture of reaction: img1 BB html

Сoding to search: TlCl + 2 LiCH3 + CH3I = TlCH33 + LiCl + LiI

Add / Edited: 11.12.2019 /

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