Na3[RhCl6] + NaOH + NaClO + H2O = Rh(OH)4 + NaCl |

2Na₃[RhCl₆] + 6NaOH + NaClO + H₂O → 2Rh(OH)₄ + 13NaCl

The reaction between hexachlororhodate(III) sodium, sodium hydroxide, sodium hypochlorite and water with the formation of hydroxide, rhodium(IV) and sodium chloride.

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The reaction between hexachlororhodate(III) sodium, sodium hydroxide, sodium hypochlorite and water with the formation of hydroxide, rhodium(IV) and sodium chloride

2Na₃[RhCl₆] + 6NaOH + NaClO + H₂O → 2Rh(OH)₄ + 13NaCl

Picture of reaction:

Сoding to search: 2 Na3RhCl6 + 6 NaOH + NaClO + H2O = 2 RhOH4 + 13 NaCl

Add / Edited: 11.12.2019 /

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The reaction between hexachlororhodate(III) sodium, sodium hydroxide, sodium hypochlorite and water with the formation of hydroxide, rhodium(IV) and sodium chloride

2Na3[RhCl6] + 6NaOH + NaClO + H2O → 2Rh(OH)4 + 13NaCl

Picture of reaction:

Сoding to search: 2 Na3RhCl6 + 6 NaOH + NaClO + H2O = 2 RhOH4 + 13 NaCl

Add / Edited: 11.12.2019 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

2Na₃[RhCl₆] + 6NaOH + NaClO + H₂O → 2Rh(OH)₄ + 13NaCl

Add / Edited: 11.12.2019 /