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The reaction between the phosphide of strontium and hydrochloric acid with the formation of chloride of strontium and phosphine

Sr3P2 + 6HCl → 3SrCl2 + 2PH3

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The reaction between the phosphide of strontium and hydrochloric acid with the formation of chloride of strontium and phosphine.

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Сoding to search: Sr3P2 + 6 HCl = 3 SrCl2 + 2 PH3

Add / Edited: 11.12.2019 /

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