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The reaction between iodine vanadium(II) and oxygen with the formation of vanadium oxide(V) and iodine

4VI2 + 5O2 → 2V2O5 + 4I2

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The reaction between iodine vanadium(II) and oxygen with the formation of vanadium oxide(V) and iodine.

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Сoding to search: 4 VI2 + 5 O2 = 2 V2O5 + 4 I2

Add / Edited: 12.12.2019 /

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