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The reaction between chloride of vanadium(II) and hydrogen fluoride with the formation of fluoride of vanadium(III), hydrochloric acid and hydrogen

2VCl2 + 6HF → 2VF3 + 4HCl + H2

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The reaction between chloride of vanadium(II) and hydrogen fluoride with the formation of fluoride of vanadium(III), hydrochloric acid and hydrogen.

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Сoding to search: 2 VCl2 + 6 HF = 2 VF3 + 4 HCl + H2

Add / Edited: 12.12.2019 /

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