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The reaction between the hydroxide of vanadium(IV) and sodium hydroxide with the formation of Vanadate of sodium and water

4V(OH)4 + 2NaOH → Na2V4O9 + 9H2O


The reaction between the hydroxide of vanadium(IV) and sodium hydroxide with the formation of Vanadate of sodium and water.


Picture of reaction: img1 BB html

Сoding to search: 4 VOH4 + 2 NaOH = Na2V4O9 + 9 H2O

Add / Edited: 12.12.2019 /

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