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The reaction between the zirconium, hydrochloric acid and nitric acid with the formation of chloride of zirconium(IV) oxide nitrogen(II) and water

3Zr + 12HCl + 4HNO3 → 3ZrCl4 + 4NO + 8H2O


The reaction between the zirconium, hydrochloric acid and nitric acid with the formation of chloride of zirconium(IV) oxide nitrogen(II) and water.

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Сoding to search: 3 Zr + 1 2HCl + 4 HNO3 = 3 ZrCl4 + 4 NO + 8 H2O

Add / Edited: 12.12.2019 /

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