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The reaction between zirconium, calcium fluoride and hydrochloric acid with the formation of the fluoride of zirconium(IV), calcium chloride and hydrogen

Zr + 2CaF2 + 4HCl → ZrF4 + 2CaCl2 + 2H2

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The reaction between zirconium, calcium fluoride and hydrochloric acid with the formation of the fluoride of zirconium(IV), calcium chloride and hydrogen.

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Сoding to search: Zr + 2 CaF2 + 4 HCl = ZrF4 + 2 CaCl2 + 2 H2

Add / Edited: 12.12.2019 /

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