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The reaction between sulfide scandium and bromoiodide with the formation of bromide of scandium and hydrogen sulfide

Sc2S3 + 6HBr → 2ScBr3 + 3H2S


The reaction between sulfide scandium and bromoiodide with the formation of bromide of scandium and hydrogen sulfide.


Picture of reaction: img1 BB html

Сoding to search: Sc2S3 + 6 HBr = 2 ScBr3 + 3 H2S

Add / Edited: 12.12.2019 /

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