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The reaction between chloride of niobium(V) and iron with formation of chloride of niobium(IV) and iron(II) chloride

2NbCl5 + Fe → 2NbCl4 + FeCl2


The reaction between chloride of niobium(V) and iron with formation of chloride of niobium(IV) and iron(II) chloride.

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Picture of reaction: img1 BB html

Сoding to search: 2 NbCl5 + Fe = 2 NbCl4 + FeCl2

Add / Edited: 12.12.2019 /

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